x^2-(x^2/4)=3

Solution for x^2-(x^2/4)=3 equation:

x^2-(x^2/4)=3

We move all terms to the left:

x^2-(x^2/4)-(3)=0

We get rid of parentheses

x^2-x^2/4-3=0

We multiply all the terms by the denominator


-x^2+x^2*4-3*4=0

We add all the numbers together, and all the variables

-1x^2+x^2*4-12=0

Wy multiply elements

-1x^2+4x^2-12=0

We add all the numbers together, and all the variables

3x^2-12=0

a = 3; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·3·(-12)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*3}=\frac{12}{6}
=2
$